Answer:
COP=13.37
Explanation:
Considering the allowed temperature difference the temperature in the evaporator will be 20°. The enthalpy and entropy at this temperature are obtained from table for the saturated vapor phase:
h_1=261.64 kJ/kg
s_1=0.92254 kJ/kgK
The enthalpy at state 2 is determined from the given condenser pressure and the condition s_2 = s_1 with data from table using interpolation:
h_2=273.18 kJ/kg
The enthalpy at states 3 and 4 is determined from the saturated liquid value for the condenser pressure from table:
h_3=h_4=107.34 kJ/kg
the COP is then:
COP=qL/w
= h_1- h_4/ h_2- h_1
=13.37