Answer:
equivalent power = 6.60 × [tex]10^{12}[/tex] W
Explanation:
given data
coal train length = 1.5 km = 1500 m
contain = 120 cars
holding= 110 tonnes of coal each
train traveling speed = 100 km/h = 27.78 m/s
to find out
equivalent power in watts
solution
we take here energy produce by coal is 27 × [tex]10^{6}[/tex] J/kg
and here total coal = 120 × 110 × 10³ kg
sop here energy produce by total coal is
energy produce by total coal = 27 × [tex]10^{6}[/tex] × 120 × 110 × 10³
and time required to cross that distance is
time = [tex]\frac{distance}{speed}[/tex]
time = [tex]\frac{1500}{27.78}[/tex]
time = 53.99 sec
so here equivalent power will be
equivalent power = [tex]\frac{energy}{time}[/tex]
equivalent power = [tex]\frac{27*10^6*120*110*10^3}{53.99}[/tex]
equivalent power = 6.60 × [tex]10^{12}[/tex] W