Answer:
[tex]T(N) = 0.2n + 47.4[/tex]
Step-by-step explanation:
We are given the following in the question:
A cricket produces 113 chirps per minute at 70°F and 163 chirps per minute at 80°F.
Let T be the temperature and N be the number of chirps, then the linear equation can be written as:
[tex]T(N) = aN + b[/tex]
where a and b are constants.
T = 70, N = 113
[tex]70 = 113a + b[/tex]
T = 80, N = 163
[tex]80 = 163a + b[/tex]
Solving the two equation by elimination, method, we have,
[tex]80 - 70 = 163a + b - 113a - b\\10 = 50a\\a = 0.2\\80 = 163(0.2) + b\\b = 80 - 163(0.2) = 47.4[/tex]
Thus, linear equation that models the temperature T as a function of the number of chirps per minute N is:
[tex]T(N) = 0.2N + 47.4[/tex]