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Potassium ions (K+) move across a 7.0 -mm- thick cell membrane from the inside to the outside. The potential inside the cell is −70.0 mV, and the potential outside is zero. What is the change in the electrical potential energy ΔU electric of the potassium ions as they move across the membrane?

Respuesta :

Explanation:

Relation between potential energy and charge is as follows.

           U = qV

or,    [tex]\Delta U = q \times \Delta V[/tex]

                   = [tex]1.6 \times 10^{-19} \times 70 \times 10^{-3}[/tex]

                   = [tex]112 \times 10^{-22}[/tex] J

or,                = [tex]1.12 \times 10^{20} J[/tex]

Therefore, we can conclude that change in the electrical potential energy [tex]\Delta U[/tex] is [tex]1.12 \times 10^{20} J[/tex].

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