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369 minus 4An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic sound that travels 1530 m/s in seawater, and finds a 10-second time delay of the echo to the ocean floor and back. The ocean depth there is__________.

Respuesta :

Answer:

7650 m.

Explanation:

Ocean floor depth, d is:

d = v * t,

where,

d = the distance from the vessel to the ocean floor (or the depth)

v = 1530 m/s = velocity of the ultrasonic sound

t = t_echo/2 = time that the ultrasonic sound needs to reach the ocean floor

t_echo = 10 s = time that the ultrasonic sound needs to reach the ocean floor and return back to the vessel.

d = v * t

= v * t_echo/2

= 1530 * 10/2

= 7650 m.