Answer:
The new volume is 7,606.96 Liter.
Explanation:
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas in the balloon = 0.918 atm
[tex]P_2[/tex] = final pressure of gas in the balloon = 0.0012 atm
[tex]V_1[/tex] = initial volume of gas in the balloon = [tex]11.1 L[/tex]
[tex]V_2[/tex] = final volume of gas in the balloon = ?
[tex]T_1[/tex] = initial temperature of gas in the balloon = [tex]15^oC=273+15=288K[/tex]
[tex]T_2[/tex] = final temperature of gas in the balloon = [tex]-15^oC=273-15=258K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{0.918 atm\times 11.1 L}{288 K}=\frac{0.0012 atm\times V_2}{258 K}[/tex]
[tex]V_2=\frac{0.918 atm\times 11.1 L\times 258 K}{288 K\times 0.0012 atm}[/tex]
[tex]V_2=7,606.97 L[/tex]
The new volume is 7,606.96 Liter.
