Calculate the molar mass of naphthalene, the organic compound in mothballs, if a solution prepared by dissolving 5.00 g of naphthalene in exactly 100 g of benzene has a freezing point 2.0°C below that of pure benzene. (Kf of benzene is 5.12°C/m.)

Respuesta :

Answer : The molar mass of naphthalene is, 128 g/mol

Explanation :  Given,

Molal-freezing-point-depression constant [tex](K_f)[/tex] for benzene = [tex]5.12^oC/m[/tex]

Mass of naphthalene (solute) = 5.00 g

Mass of benzene (solvent) = 100 g  = 0.100 kg

Formula used :  

[tex]\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of naphthalene}}{\text{Molar mass of naphthalene}\times \text{Mass of benzene in Kg}}[/tex]

where,

[tex]\Delta T_f[/tex] = change in freezing point  = [tex]2.0^oC[/tex]

[tex]\Delta T_s[/tex] = freezing point of solution

[tex]\Delta T^o[/tex] = freezing point of benzene

i = Van't Hoff factor = 1 (for naphthalene electrolyte)

[tex]K_f[/tex] = freezing point constant for benzene = [tex]5.12^oC/m[/tex]

m = molality

Now put all the given values in this formula, we get

[tex]2.0^oC=1\times (5.12^oC/m)\times \frac{5.00g}{\text{Molar mass of naphthalene}\times 0.100kg}[/tex]

[tex]\text{Molar mass of naphthalene}=128g/mol[/tex]

Therefore, the molar mass of naphthalene is, 128 g/mol