Answer:
The margin of error for a 90% confidence interval is 16.4
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 25
Standard deviation = 50
[tex]z_{critical}\text{ at}~\alpha_{0.10} = \pm 1.64[/tex]
Margin of error =
[tex]z_{critical}\times \dfrac{\sigma}{\sqrt{n}}[/tex]
Putting the values, we get,
[tex]1.64\times \dfrac{50}{\sqrt{25}} = 16.4[/tex]
Thus, the margin of error for a 90% confidence interval is 16.4
