Explanation:
Species present are [tex]H_{2}O(l)[/tex], [tex]Na^{+}(aq)[/tex] and [tex]Cl^{-}(aq)[/tex]. Now, we will calculate the number of componenets present as follows.
C = n - E
where, E = number of independent equations
n = number of phases present
Therefore, we will calculate the number of components as follows.
C = 3 - 1
= 2
Since, sodium chloride (NaCl) will tend to form a homogeneous mixture in water. Therefore, phase will be equal to 1.
Therefore, it means that there are two components present in one phase.