Imagine another solar system, with a star more massive than the Sun. Suppose a planet with the same mass as Earth orbits at a distance of 1 AU from the star. How would the planet's year (orbital period) compare to Earth's year?

Respuesta :

Answer:

The planet and the Earth has the same orbital period.

Explanation:

The period can be determined by means of Kepler's third law:

[tex]T^{2} = r^{3}[/tex]  (1)  

Where T is the period of revolution and r is the orbital radius.

[tex]\sqrt{T^{2}} = \sqrt{r^{3}}[/tex]

[tex]T = \sqrt{r^{3}}[/tex] (2)

An astronomical unit (AU) is the distance between the Earth and the Sun ([tex]1.50x10^{8} km[/tex]).

Then, replacing that value in equation 2 it is gotten:

[tex]T = \sqrt{(1)^{3}} [/tex]

[tex]T = 1 AU[/tex]

But 1 year is equivalent to 1 AU according to Kepler's third law since 1 year is the orbital period of the Earth.

[tex]T = 1 AU \cdot \frac{1year}{1AU}[/tex] ⇒ [tex]1 year[/tex]

   

Hence, the planet and the Earth has the same orbital period.

     

Summary:

The planet takes the same time as the Earth to go around its host star.