Answer:
The answer to the question is
The value of the equilibrium constant = 2.16×10⁻¹
Explanation:
To solve the question we write out the equation as follows
N₂ (g)+ H₂ (g) → 2NH₃ (g)
Given that
Partial pressure of N₂ (g), PN₂ = 3 atm
Partial pressure of H₂ (g) PH₂= 5 atm
and Partial pressure of NH₃ (g), PNH₃ = 2 atm
Given the partial pressures of the reacting gases at equilibrium such that the partial pressure of N₂ is given by PN₂ and the partial pressure of H₂ is given by PH₂ while the partial pressure of NH₃ is given by PNH₃ the expression for equilibrium constant in terms of partial pressure kp can be written as
[tex]K_{p} = \frac{(PNH_{3}) ^{2} }{(PN_{2})(PH_{2} }[/tex] Hence we have
Kp = 2²/(5×3) = 2.16×10⁻¹
Therefore the equilibrium constant = 2.16×10⁻¹
