Respuesta :
Nickel contains more atoms.
Explanation:
Number of atoms is determined by the Avogadro number.
1 mole of substance contains 6.022 X 10²³ atoms.
Given:
Mass of Nickel, Ni = 3.89g
Molecular weight of Ni = 58.6934g
Number of moles of Ni = 3.89/58.6934g
Number of atoms of Ni = [tex]\frac{3.89 X 6.022 X 10^2^3}{58.6934}[/tex]
Number of atoms of Ni = 0.39 X 10²³
Mass of silver, Ag = 6.61g
Molecular weight of Ag = 107.8682g
Number of moles of Ag = 6.61/107.8682
Number of atoms of Ag = [tex]\frac{6.61 X 6.022 X 10^2^3}{107.8682}[/tex]
Number of atoms of Ag = 0.36 X 10²³
Therefore, Nickel contains for atoms.
The sample which contains more atoms is; 3.89g of Nickel
Atoms and Avogadro's number
By Avogadro's law; one mole of each substance contains equal number of atoms.
- On this note, we must evaluate the number of moles of each element sample.
No. of moles of Nickel in 3.89g of nickel is;
- Moles(nickel) = 3.89/59 = 0.066moles
- Moles of (Silver) = 6.61/108 = 0.061
Hence, the sample with most number of atoms is Nickel.
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