Answer: (a) W = -2.23 J
(b) W = -326J
Note: T = 305K; P = 1.79 atm; V = 4.29 L are the correct parameters
Explanation:
(A) using W = -Pex * ΔV
Pex = 1.00 atm, Vf = 6.52 L, Vi = 4.29 L
W = - 1.00 * ( 6.52 - 4.29) = (- 1.00 * 2.23) J
W = -2.23 J
(B) Using W = -nRTln(Vf/Vi)
R = 0.082 atmL/mol/K or 8.314 J/mol/K
T= 305 K
Vf = 6.52 L, Vi = 4.29 L
P = 1.79 atm
n = ?
Solving for n using PV = nRT
n = PV/RT
n = 1.79 * 4.29 / (0.082 * 305)
n = 0.3070418 moles
Solving for work done
W = - 0.3070418 * 8.314 * 305 * ln(6.52/4.29)
W = - 325. 906J
W = -326J