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Two identical metal spheres A and B are connected by a metal rod. Both are initially neutral. 1.0x10^12 electrons are added tothe sphere A, then the connecting rod is removed.

Afterwards what is the charge of A and the charge ofB?

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Answer:

Charge on each metal sphere will be [tex]8\times 10^{8}C[/tex]

Explanation:

We have given number of electron added to metal sphere A [tex]n=10^{12}electron[/tex]

As both the spheres are connected by rod so half -half electron will be distributed on both the spheres.

So electron on both the spheres [tex]=\frac{10^{12}}{2}=5\times 10^{11}electron[/tex]

We know that charge on each electron [tex]e=1.6\times 10^{-19}C[/tex]

So charge on both the spheres will be equal to [tex]q=1.6\times 10^{-19}\times 5\times 10^{11}=8\times 10^{8}C[/tex]

So charge on each metal sphere will be equal to [tex]8\times 10^{8}C[/tex]