Answer:
Explanation:
Given
Two charges are separated by a distance d and exert a mutual attractive force F on each other.
Suppose [tex]q_1[/tex] and [tex]q_2[/tex] is the charge so force is given by
[tex]F=\frac{kq_1q_2}{d^2}-----1[/tex]
When distance is decrease to [tex]\frac{d}{2}[/tex]
Force is given by
[tex]F'=\frac{kq_1q_2}{(\frac{d}{3})^2}[/tex]
[tex]F'=\frac{9kq_1q_2}{d^2}-----2[/tex]
divide 1 and 2
[tex]\frac{F}{F'}=\dfrac{\frac{kq_1q_2}{d^2}}{\frac{9kq_1q_2}{d^2}}[/tex]
[tex]F'=9 F[/tex]
thus the new force become 9 times of previous force
