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A 440-Hz tuning fork is now used with a closed-end tube resonating column to determine the velocity of sound in a different gas than air. If the spacings between resonances are 1.10 m, what is the velocity of sound in this medium?

Respuesta :

Answer:

Explanation:

Given

frequency [tex]\nu =440\ Hz[/tex]

Spacing between the resonance is [tex]=1.10[/tex]  

For one end closed resonance spacing is given by

Resonance spacing[tex]=\frac{\lambda }{4}[/tex]

[tex]\lambda =4\times 1.1[/tex]

[tex]\lambda =4.4\ m[/tex]

and velocity is given by

[tex]velocity=frequency\times wavelength[/tex]

substituting the values we get

[tex]v=440\times 4.4[/tex]

[tex]v=1936\ m/s[/tex]

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