Answer:
(5,11)
Step-by-step explanation:
We have that point P is located at (2,2) and point T is located at (7,17).
We want to the coordinates of the point that partitions the directed line segment PT in the ratio m:n=3:2.
The section formula is given by:
[tex](\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})[/tex]
We substitute the point and the ratio to obtain:
[tex](\frac{3*7+2*2}{3+2},\frac{3*17+2*2}{3+2})[/tex]
Simplify to obtain:
[tex](\frac{21+4}{5},\frac{51+4}{5})[/tex]
This gives us:
[tex](\frac{25}{5},\frac{55}{5})[/tex]
Finally we obtain:
[tex](5,11)[/tex]
