Suppose you are planning to study a species of squid at a local wildlife preserve, but out of the 34 locations for which they could be located, only 14 of them contain the species. Due to time constraints, you randomly select 5 locations. What is the probability that 3 of those contain squid and the remaining 2 locations do not contain squid?

Respuesta :

Answer:

Therefore, the probability is P=0.24.

Step-by-step explanation:

We know that of the 34 locations for which they could be located a species of squid, only 14 of them contain the species. Therefore, 20 locations do not contain squid.

The probability that the locations do contain squid is:

[tex]P_1=\frac{14}{34}=\frac{7}{17}=0.41[/tex]

The probability that the locations do not contain squid is:

[tex]P_2=\frac{20}{34}=\frac{10}{17}=0.59[/tex]

If select 5 locations, we calculate the probability that 3 of those contain squid and the remaining 2 locations do not contain squid.

[tex]P=C_3^5\cdot 0.41^3\cdot 0.59^2\\\\P=\frac{5!}{3!(5-3)!}\cdot 0.024\\\\P=10\cdot 0.024\\\\P=0.24[/tex]

Therefore, the probability is P=0.24.