Answer:
Explanation:
If E₀ is the electric field outside the smaller sphere and r is the radius of larger sphere.
E₀ = kQ/r²
The radius of the larger sphere is 3r and the charge on both sphere is same then the electric field outside the larger sphere is given as
E = kQ/(3r)² = kQ/9r² = 1/9 (kQ/r²)= 1/9 x E₀
hence the correct option is e.
