A person gets into an elevator at the lobby level of a hotel together with his 28-kg suitcase, and gets out at the 10th floor 35 m above. Determine the amount of energy consumed by the motor of the elevator that is now stored in the suitcase. Assume that the vibrational effects in the elevator are negligible.

The amount of energy consumed by the motor of the elevator that is now stored in the suitcase is equal to the potential energy gained by the suitcase.

Potential energy is the energy by virtue of its position. And can be written as;

P.E = mgh

Given

mass m = 28kg

height h = 35m

Acceleration due to gravity g = 9.8m/s^2

P.E = 28 × 35 × 9.8

P.E = 9604J = 9.60KJ

Therefore, the amount of energy consumed by the motor of the elevator that is now stored in the suitcase is 9604J

Histrionicus Histrionicus · Answer 2 · 2021-11-30T17:55:27+01:00

In the given case, the amount of energy consumed by the motor of the elevator that is now stored in the suitcase - 9604 Kilojoules

Given:

weight of suitcase - 28 kg

height = 35 m

Solution:

We know that

energy consumed by the motor = energy is given to the suitcase

And, energy is given to the suitcase = potential energy of suitcase

potential energy is the stored energy that depends upon the relative position of various parts of a system
potential energy depends on the mass, height and gravitational force acting on it

P.E = mgh

here, g = [tex]9.8 \ m/s^2[/tex]

Placing the given values,

[tex]= 28 \times 35 \times 9.8\ kj[/tex]

= 9604 Kilojoules

Thus, In the given case, the amount of energy consumed by the motor of the elevator that is now stored in the suitcase - 9604 Kilojoules

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