Answer:
[tex] n = \frac{10^{-9}C}{1.6 x10^{-19}C}= 6.25 x10^{9} electrons \approx 6.3 x10^{9} electrons[/tex]
Explanation:
For this case we know that the charge associated to the transferred electrons of the small spark is [tex]10^{-19}C[/tex] and we want to find the number of electrons transferred.
From the properties of matter we know that the charge of the electron is
[tex] q_e = |-1.6 x10^{-19}C |= 1.6 x10^{-19}C[/tex]
And we know that the total charge is given by this expression:
[tex] Q = n e[/tex]
Where Q represent the charge, n the number of electrons and e the charge of the electron.
If we solve for n we got:
[tex] n = \frac{Q}{e}[/tex]
And replacing we got:
[tex] n = \frac{10^{-9}C}{1.6 x10^{-19}C}= 6.25 x10^{9} electrons \approx 6.3 x10^{9} electrons[/tex]