A person shuffles across the rug and then place his finger near his friend's nose, causing a small spark that transfers about 10^−9C of charge from the person to his friend. Determine the number of electrons transferred. e=1.6×10^−19C.

Express your answer using two significant figures.

Respuesta :

Answer:

[tex] n = \frac{10^{-9}C}{1.6 x10^{-19}C}= 6.25 x10^{9} electrons \approx 6.3 x10^{9} electrons[/tex]

Explanation:

For this case we know that the charge associated to the transferred electrons of the small spark is [tex]10^{-19}C[/tex] and we want to find the number of electrons transferred.

From the properties of matter we know that the charge of the electron is

[tex] q_e = |-1.6 x10^{-19}C |= 1.6 x10^{-19}C[/tex]

And we know that the total charge is given by this expression:

[tex] Q = n e[/tex]

Where Q represent the charge, n the number of electrons and e the charge of the electron.

If we solve for n we got:

[tex] n = \frac{Q}{e}[/tex]

And replacing we got:

[tex] n = \frac{10^{-9}C}{1.6 x10^{-19}C}= 6.25 x10^{9} electrons \approx 6.3 x10^{9} electrons[/tex]