Answer:
95.44%
Step-by-step explanation:
Mean rate (μ) = 160 euros
Standard deviation (σ) = 8 euros
For any given rate, X, the z-score is:
[tex]z=\frac{X-\mu}{\sigma}[/tex]
For X = 144 euros:
[tex]z=\frac{144-160}{8}\\ z=-2[/tex]
For X= 176 euros
[tex]z=\frac{176-160}{8}\\ z=2[/tex]
In a standard distribution, a z-score of -2 corresponds to the 2.28th percentile, while a z-score of 2 corresponds to the 97.72th percentile.
Therefore, the percentage of hotels with rates between 144 and 176 euros is:
[tex]P=97.72-2.28\\P=95.44\%[/tex]