Answer:
302.076411995 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
[tex]\mu[/tex] = Coefficient of friciton = 0.102
[tex]a=-\frac{f}{m}\\\Rightarrow a=-\frac{\mu mg}{m}\\\Rightarrow a=-\mu g[/tex]
[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2(-\mu g)}\\\Rightarrow s=\dfrac{0^2-(\dfrac{55\times 1609.34}{3600})^2}{2\times 0.102\times -9.81}\\\Rightarrow s=302.076411995\ m[/tex]
The stopping distance is 302.076411995 m.
