The inequality [tex]x-3 \geq 0[/tex] can be used to find the domain of [tex]f(x)=\sqrt{x-3}[/tex]
Answer: Option B
Step-by-step explanation:
We have [tex]f(x)=\sqrt{x-3}[/tex], domain is the set of all possible x-values which will make the function "work", and will output real y-values. Basically to find domain of any function means to find range of values of x that will give real values of y.
For the equation [tex]f(x)=\sqrt{x-3}[/tex] , we know that there's no value ( iota or complex numbers are there but here we will deal with real numbers ) of negative numbers under square root
∴[tex]{(} x-3 {)}[/tex] must be greater than or equal to 0.
⇒ [tex]x-3 \geq 0[/tex]
