Answer:
The pOH of a solution that has a pH of 6.25 at 100°C is 7.75 (option D)
Explanation:
pOH + pH = 14
pOH = 14 - 6.25
pOH = 7.75
Therefore, at 100°C, the Kw of water is 5.6x10⁻¹³ and the pOH of a solution that has a pH of 6.25 at 100°C is 7.75.
Thus, option D, is the correct answer.
Answer:
D. 7.75.
Explanation:
Equation for the dissociation of water:
H2O(aq) --> H+(aq) + OH-(aq)
[H+][OH-] = Kw
The constant, Kw, is the ionic product of water. The product of concentrations of H+ and OH- ions in water at a particular temperature is known as ionic product of water.
Kw = 5.6x10−13
Since,
pH + pOH = 14
pH = 6.25
6.25 + pOH = 14
Therefore,
pOH = 14 - 6.25
= 7.75.
