Answer:
v =-98t at t seconds
Step-by-step explanation:
given that the position function
[tex]s(t) = -49t^2 + 800[/tex]
gives the hieght (in meters) of an object that has fallen for t seconds from a height of 800 meters
To find out the velocity at time t.
Velocity is nothing but rate of change of position
In other words, velocity is the derivative of position function.
So to find out velocity at time t, we differentiate the position function.
[tex]s'(t) = -49(2t) \\v(t) = -98t[/tex]
Velocity function is
v = -98t, at t seconds.
