Respuesta :
Answer:
The correct answer is b) 2.01 moles
Explanation:
We use the formula PV=nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol.
1 atm x 45 l = n x 0, 082 l atm/K mol x 273 K
n =1 atm x 45 l /0, 082 l atm/K mol x 273 K
n= 2, 010184937 mol
The number of moles of gas in 45 liters of oxygen at STP is 2.01 moles.
Calculation of the number of moles of gas at STP:
It is known that at standard temperature and pressure, the pressure (P) is 1 atm and the temperature (T) is considered as 273 K.
The volume (V)of oxygen given in the question is 45 L.
Now, the number of moles of gas can be determined by using the formula,
PV = nRT
By putting the values we get,
[tex]n = \frac{PV}{RT} \\n = \frac{1*45}{0.0821*273} \\n = 2.01 moles[/tex]
Thus, the correct answer is option b, that is, 2.01 moles.
Find out more information about number of moles calculation here:
https://brainly.com/question/15230465
