Answer:
[tex]a=\frac{b-18x}{3x-8}\\b=3ax-8a+18x[/tex]
Step-by-step explanation:
Solving for A:
[tex]a(3x-8)=b-18x[/tex] - Given
[tex]\frac{a(3x-8)}{(3x-8)}=\frac{b-18x}{(3x-8)}[/tex] - Divide both sides by 3x-8 to isolate a
[tex]a = \frac{b-18x}{3x-8}[/tex] - Simplify
Solving for B:
[tex]a(3x-8)=b-18x[/tex] - Given
[tex]3ax-8a=b-18x[/tex] - Distribute the parenthesis (distributive property)
[tex]3ax-8a+18x=b[/tex] - Add 18x to both sides to isolate b
