Answer : The length of protein will be, 96.8 A⁰
Explanation :
First we have to calculate the amino acid residue.
[tex]\text{Amino acid residue}=\frac{\text{Length of single strand of protein}}{\text{Mean residue mass}}[/tex]
Given:
Length of single strand of protein = 71.0 kDa
Mean residue mass = 110 Da
[tex]\text{Amino acid residue}=\frac{71.0kDa}{110Da}=\frac{71000Da}{110Da}=645.4[/tex]
Now we have to calculate the number of turns in protein.
[tex]\text{Number of turns in protein}=\frac{\text{Amino acid residue}}{3.6\text{amino acid per turn of the alpha-helix}}[/tex]
As there are 3.6 amino acid per turn of the alpha-helix.
[tex]\text{Number of turns in protein}=\frac{645.4}{3.6}=179.28[/tex]
Now we have to calculate the length of the protein.
[tex]\text{Length of protein}=\text{Number of turns in protein}\times \text{Length of each turn}[/tex]
As, we know that the length of each turn = 0.54 A⁰
[tex]\text{Length of protein}=179.28turns\times \0.54\AA=96.8\AA[/tex]
Thus, the length of protein will be, 96.8 A⁰