Answer:
The van't Hoff factor is 2.55
Explanation:
Step 1: Data given
Osmotic pressure of CaCl2 = 0.585 atm
Osmotic pressure of urea = 0.237 atm
Concentration = 9.69 * 10^-3 M
Temperature = 25.0 °C
Step 2:
Π = iMRT
⇒ with Π = the osmotic pressure of CaCl2 = 0.585 atm
⇒ with i is the van't Hoff factor
⇒ with M = the molar concentration = 9.69 * 10^-3 M
⇒ with R = the gas constant = 0.0821 L*atm/mol*K
⇒ with T = the temperature = 25.0 °C = 298 K
0.605 atm = i(9.69 * 10^-3 M)(0.0821 L*atm/mol*K)(298K)
i = 2.55
The van't Hoff factor is 2.55
