Suppose the total number of hours adult women sleep in a day are normally distributed with a mean of 7.8 hours and a standard deviation of 1.2 hours. What number of hours represents the 90th percentile?

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Answer:

9.34 hours

Step-by-step explanation:

Mean number of hours (μ) = 7.8 hours

Standard deviation (σ) = 1.2 hours

According to a z-score table, the corresponding z-score to the 90th percentile of a normal distribution is z = 1.281

For any number of hours adult women sleep in a day, X, the z-score is:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

If z = 1.281, the value of X is:

[tex]1.281=\frac{X-7.8}{1.2}\\X=9.34\ hours[/tex]

The number of hours that represents the 90th percentile is 9.34 hours.

Answer: 9.342 hours represents the 90th percentile

Step-by-step explanation:

Since the total number of hours that adult women sleep in a day are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = number of hours.

µ = mean

σ = standard deviation

From the information given,

µ = 7.8 hours

σ = 1.2 hours

The 90th percentile is 90/100 = 0.9

Looking at the normal distribution table, the corresponding z score is 1.285

For z = 1.285,

1.285 = (x - 7.8)/1.2

Cross multiplying by 1.2, it becomes

1.2 × 1.285 = x - 7.8

1.542 = x - 7.8

x = 1.542 + 7.8

x = 9.342