Respuesta :
This is an incomplete question, here is a complete question.
The first ionization energy of a carbon atom is 1.81 aJ (attojoules).
Assuming an ionization efficiency of 53.0 %, how many such photons are needed to ionize 1.00 × 10¹⁶ atoms?
Answer : The number of photons needed to ionize 1.00 × 10¹⁶ atoms are, [tex]1.89\times 10^{16}[/tex]
Explanation : Given,
Energy = [tex]1.81aJ=1.81\times 10^{-18}J[/tex]
First we have to calculate the energy required to ionize the atom.
Energy required to ionize the atom = [tex]53.0\%\times (1.81\times 10^{-18}J0[/tex]
Energy required to ionize the atom = [tex]\frac{53.0}{100}\times (1.81\times 10^{-18}J)[/tex]
Energy required to ionize the atom = [tex]9.59\times 10^{-19}J[/tex]
Now we have to calculate the number of photons are needed to ionize 1.00 × 10¹⁶ atoms.
[tex]\text{Number of photons needed}=\frac{(Energy)\times \text{Number of atoms}}{\text{Available energy}}[/tex]
[tex]\text{Number of photons needed}=\frac{(1.81\times 10^{-18})\times (1.00\times 10^{16})}{(9.59\times 10^{-19})}[/tex]
[tex]\text{Number of photons needed}=1.89\times 10^{16}[/tex]
Thus, the number of photons needed to ionize 1.00 × 10¹⁶ atoms are, [tex]1.89\times 10^{16}[/tex]
