Answer:
[tex]P_2 = 33.297\ psi[/tex]
Explanation:
give,
Gauge pressure of car, P₁ = 30 psi
temperature,T₁ = 0° C = 0 + 273 = 273 K
Assuming temperature at the noon = 30° C
T₂ = 30 + 273 = 303 K
Pressure at this temperature, P₂ = ?
Using ideal gas equation
[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]
taking volume as in compressible V₁ = V₂
[tex]\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}[/tex]
[tex]\dfrac{30}{273}=\dfrac{P_2}{303}[/tex]
[tex]P_2 = 303\times \dfrac{30}{273}[/tex]
[tex]P_2 = 33.297\ psi[/tex]
Hence, Pressure of the at 30°C is equal to 33.297 psi.
