Respuesta :

The mass percentage of concentration is 12.43%

Data;

  • Number of moles = 1.0 mol
  • Volume = 1.0L
  • molar mass of Na2SO4 = 142.04g/mol
  • density of water = 1000g/L

Mass of Solute

Using the number of moles formula

[tex]number of moles = \frac{mass}{molar mass} \\[/tex]

let substitute the values and solve

[tex]1 = \frac{mass}{molar mass}\\mass = 1 * 142.04\\mass = 142.04g[/tex]

The density of water is given as 1000g/L

[tex]density = \frac{mass}{volume}\\ mass = density * volume\\mass = 1000 * 1\\mass = 1000g[/tex]

mass of solute = mass of solute + mass of solvent

mass of solute = 142.04 + 1000 = 1142.04g

mass percentage of concentration = ?

[tex]mass percentage conc. = \frac{mass of solute}{mass of solution} * 100\\mass percentage conc. = \frac{142.04}{1142.04} * 100\\ mass percentage conc. = 12.43%[/tex]

The mass percentage of concentration is 12.43%

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