Answer:
E = 12262 V/m
Explanation:
given,
Charge of the particle, q = +4.0 μC
mass of the ball, m = 5 g
Electric field, E = ?
Force due to weight
F = m g
Force due to electric field
F =q E
To balance the weight of particle both the forces must be equal
Electric field exerted on the ball will be equal to
m g = q E
[tex]E = \dfrac{m\ g}{q}[/tex]
[tex]E = \dfrac{5\times 10^{-3}\times 9.81}{4\times 10^{-6}}[/tex]
E = 12262 V/m
Hence, the electric field acting in the particle is equal to E = 12262 V/m
