Answer:
The uncertainty in the position of the electron is 5.787 nm
Explanation:
Δx ≥ h/(4πmΔv)
where;
h is Planck's constant and m is the mass of the object.
Planck's constant = 6.626 X 10⁻³⁴
The mass of an electron is 9.11 x 10⁻³¹kg.
Δv is the change in velocity 0.01 × 10⁶ m/s
Δx ≥ h/(4π*mΔv) = (6.626 X 10⁻³⁴)/(4π*9.11 x 10⁻³¹ *0.01 × 10⁶)
Δx ≥ 5.787 X 10⁻⁹ m
Δx ≥ 5.787 nm
Therefore, the uncertainty in the position of the electron is 5.787 nm
