Respuesta :
Answer : The mass of water would be, 8118 kg
Explanation : Given,
Mass of [tex]H_2[/tex] = 902 kg = 902000 g
Molar mass of [tex]H_2[/tex] = 2 g/mole
The electrolysis reaction of water is:
[tex]2H_2O\rightarrow 2H_2+O_2[/tex]
First we have to calculate the moles of [tex]H_2[/tex].
[tex]\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}[/tex]
[tex]\text{Moles of }H_2=\frac{902000g}{2g/mol}=451000mol[/tex]
Now we have to calculate the moles of [tex]H_2O[/tex]
From the balanced chemical reaction we conclude that,
As, 2 moles of [tex]H_2[/tex] produced from 2 moles of [tex]H_2O[/tex]
So, 451000 moles of [tex]H_2[/tex] produced from 451000 moles of [tex]H_2O[/tex]
Now we have to calculate the mass of [tex]H_2O[/tex]
[tex]\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O[/tex]
Molar mass of [tex]H_2O[/tex] = 18 g/mol
[tex]\text{Mass of }H_2O=451000mol\times 18g/mol=8118000g=8118kg[/tex]
Thus, the mass of water would be, 8118 kg
