Answer:
(a) The probability of being served Red Snapper is 0.23.
(b) The probability that at least one customer of 5 is actually served red snapper is 0.7293.
Step-by-step explanation:
Let X = A specimen was red snapper.
The probability that the fish served to a customer is a red snapper is:
P (Red Snapper) = 1 - P(Not Red Snapper)
[tex]P(X)=1 - P(X^{C})[/tex]
[tex]=1-0.77\\=0.23[/tex]
(a)
Assuming the results of the DNA analysis are valid, the probability that you are actually served red snapper the next time you order it at a restaurant is:
P (Being served Red Snapper) = 0.23.
Thus, the probability of being served Red Snapper is 0.23.
(b)
The random variable X follows a binomial distribution with parameters n = 5 and p = 0.23.
The probability distribution of binomial is:
[tex]P(X =x)={n\choose x}p^{x}(1-p)^{n-x}[/tex]
If there are 5 customers at a restaurant ordering red snapper, the probability that at least one customer is actually served red snapper is:
P (X ≥ 1) = 1 - P(X < 1)
= 1 - P (X = 0)
[tex]=1-{5\choose 0}(0.23)^{0}(1-0.23)^{5-0}\\=1-(1\times1\times0.2707)\\=1-0.2707\\=0.7293[/tex]
Thus, the probability that at least one customer of 5 is actually served red snapper is 0.7293.