Answer:
a. 0.10 < P < 0.20
b. -1.05
c. 1.2821
Explanation:
The data represents the scores in the 1st and 4th rounds. The significance level is [tex]\alpha = 0.10[/tex]
The null hypothesis H₀ = μ[tex]_{d}[/tex]
This means that there is no difference between the population mean score of the first round and the fourth round.
Alternative hypothesis:
[tex]H_{a} :\\mu _{d} \neq 0[/tex]
This means that there is a difference between the population score pf the 1st round and 4th round.
Testing
The testing method is as follows:
[tex]t= \frac{d -\mu _{d} }{\frac{sd}{\sqrt{n} } }[/tex]
This can be solved using excel to give: 0.10 < P < 0.20
For part b) the main margin for error is 90 % confidence level. This means that there is no significant difference, hence - 1.05
For part c) the confidence interval from the tables is 1.2821. This means that the confidence interval can be used to rest the hypothesis.