Answer:
Induced emf, [tex]\epsilon=9.79\times 10^7\ volts[/tex]
Explanation:
Given that,
Length of the helicopter, l = 4 m
Angular speed of the helicopter, [tex]\omega=3\ rev/s=18.84\ rad/s[/tex]
The vertical component of the Earth’s magnetic field is, [tex]B=6.5\times 10^5\ T[/tex]
We need to find the induced emf between the tip of a blade and the hub. The induced emf in terms of angular velocity of an rotating object is given by :
[tex]\epsilon=\dfrac{1}{2}B\omega l^2[/tex]
[tex]\epsilon=\dfrac{1}{2}\times 6.5\times 10^5\times 18.84\times (4)^2[/tex]
[tex]\epsilon=9.79\times 10^7\ volts[/tex]
So, the induced emf between the tip of a blade and the hub is [tex]\epsilon=9.79\times 10^7\ volts[/tex]. Hence, this is the required solution.
