Dissipated energy is 1200 J
Explanation:
The dissipated energy is the difference between the initial gravitational potential energy (GPE) of the ball at the top of the hill and after the first rebound.
The GPE of an object is the energy possessed by the object due to its position in a gravitational field; it is given by
[tex]GPE=mgh[/tex]
where
m is the mass of the object
[tex]g=10 m/s^2[/tex] is the acceleration due to gravity
h is the height of the object above the ground
For the ball in this problem,
m = 20 kg
At the top of the hill,
h = 10 m
So initial GPE is
[tex]GPE_i=(20)(10)(10)=2000 J[/tex]
After the first rebound
h = 4 m
So final GPE is
[tex]GPE_f=(20)(10)(4)=800 J[/tex]
Therefore, dissipated energy is
[tex]GPE_i-GPE_f=2000 - 800 = 1200 J[/tex]
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