Answer:
Explanation:
Given
balloon is ascending at the rate of [tex]u=12\ m/s[/tex]
Balloon is at a height of [tex]s=80\ m[/tex]
As the package is dropped from the balloon it must possess the same initial velocity as the balloon
using
[tex]v^2-u^2=2as[/tex]
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
[tex]v^2=12^2+2\times 9.8\times 80[/tex]
[tex]v^2=1712[/tex]
[tex]v=41.37\ m/s[/tex]
time taken is given by
[tex]v=u+at[/tex]
substituting values
[tex]41.37=-12+9.8\times t[/tex]
as we consider downward direction as positive
[tex]t=\frac{53.37}{9.8}[/tex]
[tex]t=5.44\ s[/tex]
therefore time taken to reach the bottom is t=5.44 s
