Respuesta :
Answer:
The mass of sodium reacted is 138 grams
Explanation:
Firstly, the chemical reaction should be represented with a balance chemical equation. The chemical equation can be written as follows.
Na = sodium
Cl2 = chlorine gas
Na + Cl2 → NaCl
The balanced equation is
2Na(s) + Cl2(g) → 2NaCl(aq)
Atomic mass of sodium = 23 grams per mol
Atomic mass of chlorine = 35.5 grams per mol
From the chemical equation the molar mass are as follows
Sodium = 2 × 23 = 46 grams
Chlorine = 35.5 × 2 = 71 grams
Sodium chloride = 2 × 23 + 2 × 35.5 = 117 grams
if 46 grams sodium reacted to produce 117 grams of sodium chloride
? grams of sodium react to produce 351 grams sodium chloride
grams of sodium reacted = (351 × 46)/117
grams of sodium reacted = 16146/117
grams of sodium reacted = 138 grams
Answer:
0.138 kg of Na.
Explanation:
Equation of the reaction
2Na(aq) + Cl2(g) --> 2NaCl(s)
By stoichiometry, since 2 moles of Na reacted with 1 mole of Cl2 to produce 2 moles of NaCl. Therefore,
Calculating the number of moles present,
Cl2:
Number of moles = mass/molar mass
Molar mass of Cl2 = 35.5 * 2
= 71 g/mol.
= 213 * 71
= 3 moles.
NaCl:
Molar mass = 23 + 35.5
= 58.5 g/mol.
Number of moles = mass/molar mass
= 351/58.5
= 6 moles.
Since they both have equal moles,
Mass of Na = number of moles * molar mass
Molar mass of Na = 23 g/mol
= 23 * 6 moles
= 138 g
= 0.138 kg of Na.
