Answer:
[tex]-x^3+x^2+x-6=0[/tex]
Step-by-step explanation:
Algebra
The equation is shown without proper format, we'll assume the correct equation is like
[tex]\displaystyle 1-\frac{2}{x-2}=x+\frac{1}{x+2}[/tex]
Multiplying all the equation by (x-2)(x+2)
[tex](x-2)(x+2)-2(x+2)=x(x-2)(x+2)+(x-2)[/tex]
Operating
[tex]x^2-4-2x-4=x^3-4x+x-2[/tex]
Rearranging and simplifying
[tex]\boxed{-x^3+x^2+x-6=0}[/tex]
