Answer:
The KE becomes 16 times larger
Explanation:
Kinetic energy =[tex]\frac{1}{2}mv^{2}[/tex]
where m = mass , v= velocity.
The velocity of the body increases from 16 m/s to 64 m/s.
v1 =16 m/s , v2=64 m/s.
The ratio of the final Kinetic to the initial Kinetic energy will give us the required answer
final Kinetic energy / initial Kinetic energy = [tex]\frac{1}{2}mv_{2}^{2} /\frac{1}{2}mv_{1}^{2}[/tex]
= [tex]v_{2}^{2}/ v_{1}^{2}[/tex]
= 64²/16²
=16 times larger
