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If the fuel he carries produces 36 kJ of heat per gram when it burns, how much fuel should he carry? (For the sake of simplicity, assume that the transfer of heat is 100 %% efficient.)

Respuesta :

Answer:

As we know that

Q = mc(T2 - T1)

Q = (2.9 kg) x (1000 g/1 kg) x (4.18 J/g*oC) x (100 oC - 24 oC)  

Q = 921272 J

so, 921272 J x (1 kJ/1000 J) x (1 g/36 kJ) = 2.6 x 101 g

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