Compare from greatest to least the accelerations of these skydivers. a) 1000-N man with 800 N of air drag. b) 800-N woman with 700 N of air drag.

Respuesta :

Answer:

a>b Man has greater acceleration than woman

Explanation:

W = Weight = 1000 N

g = Acceleration due to gravity = 9.81 m/s²

a) Mass of the person

[tex]m=\dfrac{W}{g}\\\Rightarrow m=\dfrac{1000}{9.81}\ kg[/tex]

The air drag is 800 N = D

The acceleration is given by

[tex]a=\dfrac{W-D}{m}\\\Rightarrow a=\dfrac{1000-800}{\dfrac{1000}{9.81}}\\\Rightarrow a=1.962\ m/s^2[/tex]

b) Mass of the person

W = Weight = 800 N

[tex]m=\dfrac{W}{g}\\\Rightarrow m=\dfrac{800}{9.81}\ kg[/tex]

The air drag is 700 N = D

The acceleration is given by

[tex]a=\dfrac{W-D}{m}\\\Rightarrow a=\dfrac{800-700}{\dfrac{800}{9.81}}\\\Rightarrow a=1.22625\ m/s^2[/tex]

It can seen that the acceleration on a is greater than b

a>b