Answer:
Explanation:
Given
Initial velocity of first billiard ball [tex]u_1=3.4\ m/s[/tex]
Initial velocity of second billiard ball [tex]u_2=0\ m/s[/tex]
After collision first ball comes to rest
suppose m is the mass of both the balls
Conserving momentum to get the speed of second ball after collision
Initial momentum [tex]P_i=mu_1+mu_2=m\cdot 3.4+0[/tex]
Final momentum [tex]P_f=mv_1+mv_2[/tex]
where [tex]v_1[/tex] and [tex]v_2[/tex] are the speed of first and second ball respectively
[tex]P_i=P_f[/tex]
[tex]m\cdot 3.4+0=0+m\cdot v_2[/tex]
[tex]v_2=3.4\ m/s[/tex]
thus speed of second ball after collision is equal to speed of first ball before collision
