Answer: The amount of CO that is occupied in the room is [tex]1.98\times 10^3L[/tex]
Explanation:
We are given:
Concentration of CO = [tex]8.00\times 10^2ppm=800pm[/tex] by volume
This means that [tex]800\mu L\text{ or }800\times 10^{-6}[/tex] of CO is present in 1 L of blood
To calculate the volume of cuboid, we use the equation:
[tex]V=lbh[/tex]
where,
V = volume of cuboid
l = length of cuboid = 10.99 m
b = breadth of cuboid = 18.97 m
h = height of cuboid = 11.89 m
[tex]V=10.99\times 18.97\times 11.89=2478.83m^3[/tex]
Converting this into liters, by using conversion factor:
[tex]1m^3=1000L[/tex]
So, [tex]2478.83m^3=2.479\times 10^6L[/tex]
Applying unitary method:
In 1 L of blood, the amount of CO present is [tex]800\times 10^{-6}[/tex]
So, in [tex]2.479\times 10^6L[/tex] of blood, the amount of CO present will be = [tex]\frac{800\times 10^{-6}}{1}\times 2.479\times 10^{6}=1983.2L=1.98\times 10^3L[/tex]
Hence, the amount of CO that is occupied in the room is [tex]1.98\times 10^3L[/tex]