Answer:
see explanation
Step-by-step explanation:
Using the sine and cosine ratios in the right triangle and the exact values
sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] and cos60° = [tex]\frac{1}{2}[/tex], then
sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{BC}{10}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )
2BC = 10[tex]\sqrt{3}[/tex] ( divide both sides by 2 )
BC = 5[tex]\sqrt{3}[/tex]
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cos60° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{AB}{10}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2AB = 10 ( divide both sides by 2 )
AB = 5
